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Q.

A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ?

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a

0.59V

b

0.118V

c

1.18V

d

0.059V

answer is A.

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Detailed Solution

The solution of HCl has p^H=10
Hence, [H⁺]=10^−pH=10⁻¹⁰ M
$H_{2} \to 2 H^{+} + 2 e^{-} E_{H_{2} / H^{+}} = E^{o} - \frac{0.059}{n} \log \frac{{[H^{+}]}^{2}}{p_{H_{2}}} E_{H_{2} / H^{+}} = 0 - \frac{0 .059}{2} \log \frac{{(10^{- 10})}^{2}}{1} E_{H_{2} / H^{+}} = + 0 .59 V$

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A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ?