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A hydrogen-like atom has ground state binding energy $122.4 eV$ Then :

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its atomic number is 3

a photon of 90 eV can excite it to a higher stat

a 80 eV photon cannot excite it to a higher state

to excite an $e^{-}$ minimum 91.8 eV photon is required

answer is A, D, C.

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Detailed Solution

Here, we have

$122.4 = 13.6 \times Z^{2} \Rightarrow Z = 3$

Minimum energy required for excitation

$\begin{array}{l} = 10.2 Z^{2} eV / atm \\ = 91.8 eV \end{array}$

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