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Q.

A hypothetical pulse is travelling along positive x direction on a taught string. The speed of pulse is  10 cm/s  and shape of pulse at  t=0 is given as
 y=x6+1  for  6x0
  =x+1   for  0x<1
=0   for all other value of x
If x and y are in cm, then

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a

Vertical displacement of the particle at x=1 cm at t=0.2 s  is  43 cm

b

Transverse velocity of the particle at x=1 cm  at t=0.2 s   is  43 cm/s

c

Vertical displacement of the particle at  x=1 cm at t=0.2 s  is  56 cm

d

Transverse velocity of the particle at x=1 cm  at t=0.2 s  is  53 cm/s

answer is A, C.

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Detailed Solution

Question Image

For AB : At   t = 0.2s 

y1=16(x2)        y=x6+23       x=1  cm               y=56cm

Transverse velocity = – slope × Vw =(16)×10=53cm/s

Ans. AC

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