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'A' is a steel rod of length I_A and 'B' a copper rod of length l_B. Values of l_A and l_B such that l_A -l_B = 5 cm at all temperatures, are :
(Given $α_{Cu} = 1.7 \times 10^{- 5} / {}^{o}C, α_{st e e l} = 1.1 \times 10^{- 5} / {}^{o}C$ )

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32.4 cm, 27.4 cm

21.4 cm, 16.4 cm

10.8 cm, 5.8 cm

14.2 cm, 9.2 cm

answer is C.

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Detailed Solution

$l_{A'} - l_{B'} = l_{A} (1 + α_{A} ∆ T) - l_{B} (1 + α_{B} ∆ T) = constant \Rightarrow l_{A} α_{A} = l_{B} α_{B} \Rightarrow 11 l_{A} = 17 l_{B} Also l_{A} - l_{B} = 5 So l_{A} = 14.2 cm and l_{B} = 9.2 cm$

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