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Q.

A is faster than B, A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then A’s speed is equal to.


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a

3km/hr

b

4km/hr

c

5km/hr

d

7 km/hr 

answer is A.

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Detailed Solution

Concept: Assigning variables for the speeds of A and B and the overall distance traveled allows us to begin addressing the problem. Using the relationship between speeds provided in the problem, we then determine the first equation. The relationship provided concerning times in the issue is then used to find our second equation utilizing the assumption that Time = distance/speed. To reach the desired outcome, we then solve both of the obtained equations.
We must ascertain A's speed.
Let's assume that A is moving at VA km/h and B is moving at VB km/h.
The answer to the question is that A is quicker than B.
VA>VB
Let x be the total number of steps they took.
The answer to the question is that x=24 km.
Given is that the combined speed of letters "A" and "B" is 7 km/hr.
VA+VB=7kmhr
VB=7-VA
distance = speed × time
Time taken by A =24VA
Time taken by B = 24VB
The total amount of time they took, according to the question, was 14 hours.
24VA+24VB=14
247-VA+24VAVA7-VA=14
168-24VA+24VA7VA-VA2=14
16814=14VA-VA2
16814=7VA-VA2
12=7VA-VA2
VA2-7VA+12=0
VA2-4VA-3VA+12=0
VAVA-4-3VA-4=0
VA-4VA-3=0
VA=3km/hr
VA=4kmhr
VB=7-3=4 kmhr
VB=7-4=3 km/hr
VA>VB
VA=4km/hr and VB=3km/hr
Hence, option 2 is the correct answer.
 
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