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Q.

A is twice as good as B and together they finish a piece of work in 14 days. In how many days can A alone finish the work?


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a

12

b

15

c

17

d

21 

answer is D.

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Detailed Solution

Concept: Here, we will first determine how long A and B would need to do the same amount of work if they worked together in tandem, assuming that A would require x days and B would need 2x days. The number of days it took A to finish the work alone can then be determined by solving the equation that was obtained.
Given that, A is twice as likely as B to finish the task.
As a result, B needs twice as long as A to finish the task.
If A takes x days to accomplish the task, then B should take 2x days to do the identical task, according to the question.
Furthermore, assuming that A and B do the job in 14 days.
Work completed in a single day equals the total number of days needed to accomplish the work.
One day’s work of A=1x
One day’s work of B =12x
A+B=114
1x+12x=114
On solving the above equation we get
2x=42
x=21
Hence, option 4 is the correct answer.
 
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A is twice as good as B and together they finish a piece of work in 14 days. In how many days can A alone finish the work?