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Q.

A juggler throws balls into the air. He throws one ball whenever the previous one is at its highest point. How high do the balls rise if he throws n balls each second ? Acceleration due to gravity is g .

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a

2gn2

b

g4n2

c

g2n2

d

4gn2

answer is C.

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Detailed Solution

Juggler throws n balls in one second so time interval between two consecutive throws is t=1ns    

each balls takes 1ns to reach maximum height

So  hmax = 12×gt2 = 12×g1n2

hmax =g2n2

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