A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

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g/n

g/2n²

g/2n

2 gn

answer is D.

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Detailed Solution

Time taken by ball to reach highest point $= \frac{u}{g}$
Frequency of throw $= \frac{g}{u} = n$
$\begin{array}{l} \Rightarrow u = \frac{g}{n} \\ H_{max} = \frac{u^{2}}{2 g} = \frac{{(\frac{g}{n})}^{2}}{2 g} = \frac{g}{2 n^{2}} \end{array}$

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