A kite is flying at a height of 75 meters from the ground level, attached to a string inclined at 60⁰ to the horizontal. Find the length of the string to the nearest meter.

Let AC be the string of length h and C be the point, making an angle of 60° and the kite is flying at the height (AB)= 75 m from the ground level.

In$∆ABC$,

sin 60° = $\frac{AB}{AC}$

$\Rightarrow$$\frac{\sqrt{3}}{2}$ = $\frac{75 m}{AC}$

$\Rightarrow$AC = $\frac{150 m}{\sqrt{3}}$

$\Rightarrow$AC = 86.6 m                [Taking $\sqrt{3}$ = 1.732]

$\therefore$The length of the string to the nearest meter = 86.6 m or 87 m.