Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

A kite is flying with the string inclined at $45 °$ to the horizontal. If the string is straight and 50 m long the height at which the kite is flying is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

25 \sqrt{2} m

50 \sqrt{2} m

25 m

50 m

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

It is given that a kite is flying with the string inclined at

45 °

to the horizontal.
Here h is the height of the kite which is flying with the string inclined at

45 °

to the horizontal.
In the given figure AC represents the string which is 50 m long.
Question Image

ΔABC,

sin θ = P e r p e n d i c u l a r H y p o t e n u s e

\sin 45 ° = \frac{AB}{AC}

\Rightarrow

\sin 45 ° = \frac{h}{50}

\Rightarrow \frac{1}{\sqrt{2}} = \frac{h}{50}

∵ sin 45 ° = 12

\Rightarrow h = \frac{50}{\sqrt{2}}

\Rightarrow h = \frac{2 \times 25}{\sqrt{2}}

\Rightarrow h = 25 \sqrt{2}

So we got the value of h is

25 \sqrt{2}

m.
So the height at which the kite is flying is

25 \sqrt{2}

m.
So the correct option is 1.

JEE

NEET

Foundation JEE

Foundation NEET

CBSE