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Q.

A "L" shaped conducting rod ABC is lying in xy-plane and moving with velocity V=V0i^+3V0j^ as shown in the figure. There exist a non-uniform magnetic field which depends on x and y co-ordinate as B=B0L0(x+y)(k^), where B0 and L0 are positive constants with proper dimensions. If VPVQ represents the motional induced emf between point P and Q. Then choose the CORRECT option(s).

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a

VAVB=18B0L0V0

b

VAVC=272B0L0V0

c

VCVA=272B0L0V0

d

VBVA=18B0L0V0

answer is A, C.

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Detailed Solution

For VaVB:  B=B0L0(x+L0)(k^) εind=dl.(V×B)

VaVB=B.dx.3V0=3B.V0L0L03L0(x+L0).dx

18B0L0=VA=BB

For VaVB:   Question Image

B=B0L0(3L0y)(k^)

VCVB=B.dy.V0=B0V0L0L02L0(3L0+y).dy

VCVB=9B0L02

VAVC(1892)B0L0V0=272B0L0V0

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