A ladder ‘AB’ of weight 300 N and length 5m is lying on a horizontal surface. Its centre of gravity is at a distance of ‘2m’ from end A. A weight of 80 N is attached at end B. The work done in raising the ladder to the vertical position with end ‘A’ in contact with the ground is (in J).

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Detailed Solution

P.E of the system is described by its amount of work done
$\begin{array}{l} w = w_{1} + w_{2} \Rightarrow w = m_{1} {gd}_{1} + m_{2} {gd}_{2} \\ w = 300 \times 2 + 80 \times 5 \\ w = 600 + 400 = 1000 J \end{array}$

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