A lady has 25 and 50 coin in her purse. If in all, she has 120 coins totaling . 50. The number of coins of each type in her purse,

Let the total number of 25 coins = and total number of 50 coins = . Given:Total number of coins she has = 120⇒ + = 120⇒ = 120 − [equation I ]Total amount of money = . 50 = 50 × 100 = 5000 ⇒ 25 + 50 = 5000Putting the value of from equation I,⇒ 25(120 − ) + 50 = 5000⇒ 3000 − 25 + 50 = 5000⇒ 25 = 5000 − 30002000⇒ =25⇒ = 80 Now, put this value in equation I,⇒ = 120 − ⇒ = 120 − 80⇒ = 40 Hence, the lady has 40 coins of 25 and 80 coins of 50.

A lady has 25 and 50 coin in her purse. If in all, she has 120 coins totaling . 50. The number of coins of each type in her purse,

Let the total number of 25 coins = and total number of 50 coins = . Given:Total number of coins she has = 120⇒ + = 120⇒ = 120 − [equation I ]Total amount of money = . 50 = 50 × 100 = 5000 ⇒ 25 + 50 = 5000Putting the value of from equation I,⇒ 25(120 − ) + 50 = 5000⇒ 3000 − 25 + 50 = 5000⇒ 25 = 5000 − 30002000⇒ =25⇒ = 80 Now, put this value in equation I,⇒ = 120 − ⇒ = 120 − 80⇒ = 40 Hence, the lady has 40 coins of 25 and 80 coins of 50.

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A lady has 25𝑝 and 50𝑝 coin in her purse. If in all, she has 120 coins totaling 𝑅𝑠. 50. The number of coins of each type in her purse,

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90 , 30

60 , 60

40 , 80

70 , 50

answer is C.

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Detailed Solution

Let the total number of 25𝑝 coins = 𝑥 and total number of 50𝑝 coins = 𝑦. Given:
Total number of coins she has = 120
⇒ 𝑥 + 𝑦 = 120
⇒ 𝑥 = 120 − 𝑦 [equation I ]
Total amount of money = 𝑅𝑠. 50 = 50 × 100 = 5000 𝑝𝑎𝑖𝑠𝑎
⇒ 25𝑥 + 50𝑦 = 5000
Putting the value of 𝑥 from equation I,

⇒ 25(120 − 𝑦) + 50𝑦 = 5000
⇒ 3000 − 25𝑦 + 50𝑦 = 5000
⇒ 25𝑦 = 5000 − 3000
2000
⇒ 𝑦 =
25
⇒ 𝑦 = 80
Now, put this value in equation I,

⇒ 𝑥 = 120 − 𝑦
⇒ 𝑥 = 120 − 80
⇒ 𝑥 = 40
Hence, the lady has 40 coins of 25𝑝 and 80 coins of 50𝑝.

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