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A lamp draws the current of $0.5$ $A$ when it is connected to $60$ $V$ source, the resistance of the lamp is [[1]] $Ω$ .

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Detailed Solution

A lamp draws the current of

0.5

A

when it is connected to

60

V

source, the resistance of the lamp is

120 Ω

.
It is given that the current of

0.5 A

flows through the lamp when connected to the

60 V

.
From the Ohm’s law, “the potential difference across two terminals is directly proportional to the current flowing through it provided the physical conditions remains the same.” Mathematically,

V = IR

\Rightarrow R = \frac{V}{I}

Where

R, V

and

I

are the resistance, potential difference and the current flowing through the circuit respectively.
On substituting the given values, we get

R = \frac{60}{0.5}

\Rightarrow R = 120 Ω

Hence, the resistance of the lamp is

120 Ω

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