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A lamp radiates power P₀ uniformly in all directions, the amplitude of electric field strength E₀ at a distance r from it is

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$E_{0} = \sqrt{\frac{P_{0}}{8 π ε_{0} c r}}$

$E_{0} = \sqrt{\frac{P_{0}}{2 π ε_{0} c r^{2}}}$

$E_{0} = \frac{P_{0}}{2 π ε_{0} c r^{2}}$

$E_{0} = \sqrt{\frac{P_{0}}{4 π ε_{0} c r^{2}}}$

answer is B.

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Detailed Solution

$I = \frac{1}{2} \in_{0} E_{0}^{2} C = \frac{P_{0}}{4 π r^{2}}$

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