A large non-conducting plate of thickness $t (t \to 0)$ is placed normal to an external electric field. Electric field on the left and right hand side of this plate is found to be $E_{1} a n d E_{2}$ respectively as shown in figure. Choose the correct option(s).

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

If external electric field is switched off then new electric field on the either side of this plate will be $\frac{(E_{2} - E_{1})}{2}$ .

Total force on this plate will be $(\frac{A ε_{0}}{2}) (E_{2}^{2} - E_{1}^{2}),$ if A is area of the plate.

If A is the area of this large plate then total charge on this plate is A $ε_{0} (E_{2} - E_{1})$ .

Direction of external electric field in absence of the plate must be along the direction of $E_{1} a n d E_{2}$ as shown.

answer is A, B, C, D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$E_{0} + \frac{σ}{2 \in_{0}} + E_{2} E_{0} - \frac{σ}{2 \in_{0}} + E_{1}$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test