A large number of resistors $R_{1}, R_{2}, R_{3} . . . . . . R_{n}$ each of value R, are connected in series across a parallel combination of two cells, as shown in Fig. 5.115. Power dissipated in the series combination of resistors for n = 5 is 90 W and for n = 10, it is 125 W. Maximum power will be dissipated for n = :

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answer is C.

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Detailed Solution

${(\frac{E}{5 R + \frac{2}{3}})}^{2} \times 5 R = 90 {(\frac{E}{10 R + \frac{2}{3}})}^{2} \times 10 R = 125 R c o m e s o u t t o b e \frac{1}{30} Ω N o w f o r m a x p o w e r : n \times \frac{1}{30} = \frac{2}{3}; n = 20$

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