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A large plate with uniform surface charge desnity $σ$ is moving with constant speed $v$ as shown in the figure. The magnetic field at a small distance from plate is

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$μ_{0} σ v in magnitude$

$\frac{μ_{0} σ V}{2}$ in magnitude

Perpendicular to the direction of current

Parallel to the direction of current

answer is B, C.

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Detailed Solution

Current flowing per unit width $= σ \frac{dx}{dt} = σ v$

By Ampere's law $B ℓ + B ℓ = μ_{0} σ v ℓ \Rightarrow B = \frac{μ_{0} σ v}{2}$ .

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