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A large tank filled with water to a height ‘h’ is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from h to h/2 and from h/2 to zero is

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√2

$\frac{1}{\sqrt{2}}$

√2 -1

$\frac{1}{\sqrt{2} - 1}$

answer is C.

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Detailed Solution

$t = \sqrt{\frac{2}{g}} \frac{A}{a} (\sqrt{H_{1}} - \sqrt{H_{2}}) \Rightarrow \frac{t_{1}}{t_{2}} = \frac{\sqrt{h} - \sqrt{h / 2}}{\sqrt{h / 2} - \sqrt{0}}$

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