A laser pulse of wavelength 600 nm has average power of 0.5 W and duration 20 ms. Then

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A laser pulse of wavelength 600 nm has average power of 0.5 W and duration 20 ms. Then

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energy of a photon is 2.07 eV

energy of a pulse is 10 mJ

member of photons in a pulse is $3 \times 10^{16}$

momentum of a pulse is $2 \times 10^{- 12} kgm / s$

answer is A, B, C.

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Detailed Solution

$\begin{array}{l} E_{1} = \frac{h c}{λ} = \frac{12430}{6000} eV = 2.07 eV \\ E_{0} = P t = 0.5 \times 20 \times 10^{- 3} J = 10 mJ \\ n = \frac{E_{0}}{E_{1}} = \frac{10^{- 2}}{2.07 \times 1.6 \times 10^{- 19}} = 3 \times 10^{16} \end{array}$

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