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A lawn sprinkler has 20 holes, each of cross-sectional area $2.0 \times 10^{- 2} {cm}^{2}$ and is connected to a hose pipe of cross-sectional area $2.4 {cm}^{2}$ If the speed of water in the hose pipe is $1.5 {ms}^{- 1},$ the speed of water as it emerges from the holes is

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$18 {ms}^{- 1}$

$2.25 {ms}^{- 1}$

$4.5 {ms}^{- 1}$

$9 {ms}^{- 1}$

answer is C.

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Detailed Solution

$(2.4 \times 10^{- 4}) \times 1.5 = 20 \times 2 \times 10^{- 2} \times 10^{- 4} \times v$

$⇒ v = \frac{2.4 \times 1.5 \times 10^{2}}{40} {ms}^{- 1}$

$= \frac{24 \times 15}{40} {ms}^{- 1} = 9 {ms}^{- 1}$

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