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A lawn sprinkler has 20 holes, each of cross – sectional area $2 \times 10^{- 2} c m^{2}$ , and is connected to a hose pipe of cross-sectional area $2.4 c m^{2}$ . If the speed of water in the hose pipe is $1.5 m s^{- 1},$ the speed of water as it emerges from the holes in m/s is

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answer is 9.

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Detailed Solution

${2.4×1.5×10}^{-4} {=20×2×10}^{-2} {×10}^{-4} ×v, (or)$

$v= \frac{{2.4×1.5×10}^{2}}{40} {ms}^{-1} = \frac{24×15}{40} {ms}^{-1} {=9ms}^{-1}$

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