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A lead ball dropped into a lake from a diving board 5m above the water hits the water with certain velocity and then sinks to the bottom with the same constant velocity. If it reaches the bottom in 3s after it is dropped the depth
m of the lake is $______$ (g = 10 ms^–2)

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answer is 30.

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Detailed Solution

Ball dropped from 5m.

velocity of the ball when it strikes water is

v² - u² = 2gh

v = $\sqrt{2 \times 10 \times 5}$

v = 10m/s

It takes 3sec for the ball to reach the bottom with constant velocity of 3m/s

therefore depth d = 3 x 10 = 30m

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