Q.

A lead bullet penetrates into a solid object and melts. Assuming that 40% of its kinetic energy is used to heat it, the initial speed of bullet is: ( given initial temperature of the bullet = 127°C,melting point of the bullet = 327°C. latent heat of fusion of lead = 2.5×104JKg1, specific heat capacity of lead = 125J/KgK)

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a

500ms1

b

125ms1

c

250ms1

d

600ms1

answer is B.

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Detailed Solution

40% of K.E=msΔT+mLf40100×1/2mV2=ms(327127)+mLf20100×V2=200S+Lf15V2=200×125×2.5×104V2=1000×125×2.5×104×5V2=250000V=500m/s

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