A lead storage cell is discharged which causes the H₂SO₄ electrolyte to change from a concentration of 40% by weight (density = 1.260 g/ml) to 28%, by weight. The original volume of solution was 1L. Identify the correct statement(s);

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

The overall cell reaction is:

$Pb (s) + {PbO}_{2} (s) + 2 H_{2} {SO}_{4} (aq) \to 2 {PbSO}_{4} (s) + 2 H_{2} O (ℓ)$

A total of 2.0 moles of H₂SO₄ is reacted

The total charge released from anode of the cell is 1.93 x 10⁵ coulomb

The mass of electrolytic solution has decreased

answer is A, B, C, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Net cell reaction of discharge is
$Pb + {PbO}_{2} + \underset{x mole}{2 H_{2} {SO}_{4}} \to 2 {PbSO}_{4} + \underset{x mole}{2 H_{2} O}$
Initial mass of H₂SO₄ , $W_{1} = 10 \times 1.26 \times \frac{40}{100} = 504 gm$
Final mass of H₂SO₄, $W_{2} = (1260 - 98 x + 18 x) \times \frac{28}{100} = (352.8 - 22.4 x) gm$
From reaction, 504 - 98x = 352.8 - 22.4x $\Rightarrow$ x = 2