Given that

Length of each leap = 1m

Time taken for one leap movement = 1s

Journey is performed such that

Taking 5 leaps in forward direction three leaps are taken in backward direction.

Net displacement with single sequence = 5 – 3 = 2m

Time taken for this single sequence = 8s

Like wise we are asked to evaluate 13m displacement number of sequences involved

Total displacement = 13m

Total time taken = 43s

Average velocity $=\frac{13}{43}=0.3\text{m/s}$

Average speed $=\frac{43\text{m}}{43}=1\text{m/s}$