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Q.

A length of 2 m is measured using a metal tape at 10oC. It is calibrated at a temperature 30oC. The actual length is (α= 1×10-4/oC)

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a

2.004 m

b

1.996 m

c

0.004 m

d

1.004 m

answer is B.

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Detailed Solution

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Error = l=αlt2-t1=10-4(2)(30-10) = 0.0004

Actual length =measured length - error ; when metal tape is used at lower temperature.  
    Actual length = 2 – (0.004) = 1.996 m

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