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Q.

A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

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a

$g - a, g - a$

b

$g - a, g$

c

$g, g$

d

$a, g$

answer is C.

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Detailed Solution

Due to relative motion, acceleration of ball observed by observer in lift = (g – a) and for man on earth the acceleration remains g.

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