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A lift is moving down with an acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift, and a man standing
stationary on the ground are, respectively,

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a, g

(g-a), g

a, a

g, g

answer is B.

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Detailed Solution

${\vec{a}}_{b, l} = {\vec{a}}_{b} - {\vec{a}}_{l} = (g - a) ↓\Rightarrow {\vec{a}}_{b} = g ↓$

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