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Q.

A lift is moving down with an acceleration equal to the acceleration due to gravity. A body of mass M kept on the floor of the lift is pulled horizontally. If the coefficient of friction is µ then the frictional resistance offered by the body is

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a

Mg

b

zero

c

µMg/2

d

µMg

answer is C.

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Detailed Solution

Pseudo force 'ma' acting on the body is vertically upward.
 

N = mg - ma when a = g, N = 0

Frictional force = 0

Applied force F = 0

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