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Q.

A lift is moving downward with constant velocity 10m/s. A coin is dropped at height 5m from the floor of lift, find the time taken by coin to reach the floor. $(g = 10 m / s^{2})$

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a

0.5s

b

1.5s

c

1s

d

2s

answer is A.

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Detailed Solution

$S_{e r l a t i v e} = u_{r e l a t i v e} . t + \frac{1}{2} a_{r e l a t i v e} . t^{2} 4.9 = (0) t + \frac{1}{2} (9.8) t^{2} t = 1 s$

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