A light beam travelling in the x- direction is described by the electric field is given by Ey=270sinω( t-xc) . An electron is constrained to move along the y- direction with a speed of 2.0×107 ms−1 . Find the maximum magnetic force on the electron .

Maximum electric field, E0=270Vm−1 Maximum magnetic field, B0=E0c=2703×108=9×10−7T, Directed along z-direction Maximum electric force on the electron, Fe=qE0=1.6×10−19×270=4.32×10−17=2.88×10−18N

A light beam travelling in the x- direction is described by the electric field is given by Ey=270sinω( t-xc) . An electron is constrained to move along the y- direction with a speed of 2.0×107 ms−1 . Find the maximum magnetic force on the electron .

Maximum electric field, E0=270Vm−1 Maximum magnetic field, B0=E0c=2703×108=9×10−7T, Directed along z-direction Maximum electric force on the electron, Fe=qE0=1.6×10−19×270=4.32×10−17=2.88×10−18N

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A light beam travelling in the x- direction is described by the electric field is given by $E_{y} = 270 \sin ω (t- \frac{x}{c})$ . An electron is constrained to move along the y- direction with a speed of $2.0 \times 10^{7} m s^{- 1}$ . Find the maximum magnetic force on the electron .

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$2.88 \times 10^{- 15} N$

$2.88 \times 10^{- 16} N$

$2.88 \times 10^{- 17} N$

$2.88 \times 10^{- 18} N$

answer is D.

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Detailed Solution

Maximum electric field, $E_{0} = 270 V m^{- 1}$
Maximum magnetic field, $B_{0} = \frac{E_{0}}{c} = \frac{270}{3 \times 10^{8}} = 9 \times 10^{- 7} T,$
Directed along z-direction
Maximum electric force on the electron, $F_{e} = q E_{0} = 1.6 \times 10^{- 19} \times 270 = 4.32 \times 10^{- 17}$
$= 2.88 \times 10^{- 18} N$