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A light coming from a medium 1 to medium 2 at an angle of incidence 53° passes along the interface surface of the two media. If speed of light in medium 1 is 2x10⁶ m /s, then the speed of light in medium 2 is

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a

$1.3 \times 10^{6} m / s$

b

$3.3 \times 10^{6} m / s$

c

$0.5 \times 10^{6} m / s$

d

$2.5 \times 10^{6} m / s$

answer is D.

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Detailed Solution

$\begin{array}{l} θ_{1} = 53^{\circ}; θ_{2} = 90^{\circ} \\ C_{1} = 2 \times 10^{6}; C_{2} = ? \\ \frac{\sin θ_{1}}{\sin θ_{2}} = \frac{C_{1}}{C_{2}} \\ C_{2} = \frac{2 \times 10^{6} \times 1}{\sin 53^{\circ}} = 2 .5 \times 10^{6} m / s \end{array}$

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