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A light is at the top of a pole of 64 mt height. A ball is dropped from the same height from a point 20mt away from the light. Assuming that the ball falls according to the law $S = 5 t^{2}$ How fast is the shadow of the ball moving along the ground 2sec later

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-54

-64

answer is C.

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Detailed Solution

$\frac{64}{64 - s} = \frac{20 + x}{x}$ cross multiplying we get x = 20(64/s – 1)

$\frac{dx}{dt} = 20 (\frac{- 64}{s^{2}} \frac{ds}{dt}) = - 64$

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