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A light of wavelength $600 n m$ in air enters a medium of refractive index $1.5,$ Inside the medium.

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its frequency is $5 \times 10^{14} Hz$

its frequency is $7.5 \times 10^{14} Hz$

its wavelength is $900 nm$

its wavelength is $400 nm$

answer is A, C.

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Detailed Solution

$ν_{m e d} = ν_{v a c} = \frac{c}{λ_{v a c}} = \frac{3 \times 10^{8}}{600} H z = 5 \times 10^{14} H z$

Frequency is independent of medium and $λ_{med} = \frac{λ_{vac}}{μ} = \frac{c}{ν μ}$ = 400 nm

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