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Q.

A light ray is incident at angle of incidence i on a prism and deviated at an angle $δ$ .The i versus δ graph is plotted, it is found as shown below. The value of refractive index of the prism material is

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a

1.5

b

$\sqrt{2}$

c

$\sqrt{3}$

d

$\frac{5}{3}$

answer is C.

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Detailed Solution

$\begin{array}{l} δ_{m} = 60^{\circ}; i = 60^{\circ}; r = \frac{A}{2} \\ ∵ 60 = 2 \times 60 - A \\ \Rightarrow A = 60^{\circ} \Rightarrow r = 30^{\circ} \\ μ = \frac{\sin 60^{\circ}}{\sin 30^{\circ}} = \frac{\sqrt{3}}{2} \times \frac{2}{1} = \sqrt{3} \end{array}$

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A light ray is incident at angle of incidence i on a prism and deviated at an angle δ.The i versus δ graph is plotted, it is found as shown below. The value of refractive index of the prism material is