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Q.

A light ray is incident normally on a refracting surface of an equilateral prism of angle 60° and refractive index 1.5. The deviation of ray produced by the prism is

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a

45°

b

120°

c

30°

d

60°

answer is D.

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Detailed Solution

$i_{1} = O, A = 60^{\circ} r_{1} = O \begin{array}{l} A = r_{1} + r_{2} \\ \Rightarrow r_{2} = 60^{\circ} \end{array}$
$r_{2} = 60^{\circ}; but C = 42^{0} for μ = 1.5$
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so the light undergoes T.I.R
The deviation $δ = 180 - 2 r_{2} = 60 °$

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