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Q.

A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34°.  If the shaded half of the prism is knocked off, the ray will

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a

Suffer a deviation of 17°

b

Not come out of the prism

c

 Suffer a deviation of 34° 

d

Suffer a deviation of 68° 

answer is C.

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Detailed Solution

 By formula δ=(n−1)A⇒34=(n−1)A and in  the second position δ′=(n−1)A2
∴34δ′=(n−1)A(n−1)A2 or δ′=342=17∘

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