A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 340. If the shaded half of the prism is knocked off, the ray will

By formula δ=(n−1)A⇒34=(n−1)A and in the second position δ1=(n−1)A2 ∴34δ1=(n−1)A(n−1)A2 or δ1=342=170

A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 340. If the shaded half of the prism is knocked off, the ray will

By formula δ=(n−1)A⇒34=(n−1)A and in the second position δ1=(n−1)A2 ∴34δ1=(n−1)A(n−1)A2 or δ1=342=170

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A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34⁰. If the shaded half of the prism is knocked off, the ray will

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Suffer a deviation of 68⁰

Suffer a deviation of 34⁰

suffer a deviation of 17⁰

Not come out of the prism

answer is C.

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By formula $δ = (n - 1) A \Rightarrow 34 = (n - 1) A$ and in the second position $δ^{1} = (n - 1) \frac{A}{2}$
$∴ \frac{34}{δ^{1}} = \frac{(n - 1) A}{(n - 1) \frac{A}{2}} o r δ^{1} = \frac{34}{2} = 17^{0}$

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A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 340. If the shaded half of the prism is knocked off, the ray will

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A light ray is incident upon a prism in minimum deviation position and suffers a deviation of 34⁰. If the shaded half of the prism is knocked off, the ray will