A light ray travels in two media A and B with speeds 2×108 m/s and 2.4×108 m/s. The critical angle between them is

μ2μ1=V1V2=2.4×1082×108⇒μ2μ1=65⇒sin⁡C=1μ2μ1=μ1μ2⇒sin⁡C=56⇒C=sin-156

A light ray travels in two media A and B with speeds 2×108 m/s and 2.4×108 m/s. The critical angle between them is

μ2μ1=V1V2=2.4×1082×108⇒μ2μ1=65⇒sin⁡C=1μ2μ1=μ1μ2⇒sin⁡C=56⇒C=sin-156

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A light ray travels in two media A and B with speeds $2 \times 10^{8} m / s$ and $2.4 \times 10^{8} m / s$ . The critical angle between them is

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sin^-1 (8/9)

sin^-1 (5/6)

tan^-1 (5/6)

cos^-1 (5/6)

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{μ_{2}}{μ_{1}} = \frac{V_{1}}{V_{2}} = \frac{2.4 \times 10^{8}}{2 \times 10^{8}} \\ \Rightarrow \frac{μ_{2}}{μ_{1}} = \frac{6}{5} \\ \Rightarrow \sin C = \frac{1}{(\frac{μ_{2}}{μ_{1}})} = \frac{μ_{1}}{μ_{2}} \\ \Rightarrow \sin C = \frac{5}{6} \\ \Rightarrow C = \sin^{- 1} (\frac{5}{6}) \end{array}$