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A light string fixed at one end to a clamp on ground passes over a fixed pulley and hangs at the other side. It makes an angle of 30° with the ground. A monkey of mass 5 kg climbs up the rope. The clamp can tolerate a vertical force of 40 N only. The maximum acceleration in upward direction with which the monkey can climb safely is (neglect friction and take g = 10 m/s²) :

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4 m/s²

6 m/s²

2 m/s²

8 m/s²

answer is C.

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Detailed Solution

$\begin{array}{l} Tsin 30 = 40; T = m (g + a) \\ 80 = 5 [10 + a] \Rightarrow a = 6 m / s^{2} \end{array}$

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