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Q.

A light string going over a clamped pulley of mass m supports a block of mass M as shown in figure. The force on the pulley by the clamp is given by

 

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a

gM+m2+M2

b

2 mg

c

gM+m2+m2

d

2 Mg

answer is D.

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Detailed Solution

T =mg

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Force on the pulley ( other than from clamp)

Fnet=T+mg2+T2=gM+m2+M2

Since, pulley is in equilibrium, clamp will exert the same amount of force in opposite direction. Or pulley will also exert this much force on clamp.

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