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A light string of 70 cm has its two ends tied at the same level 50 cm apart. A force of 100 N is applied at a distance of 30 cm from P. The tension in part PR is

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18 N

8 N

0 N

80 N

answer is D.

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Detailed Solution

$Here T_{1} \cos (90 - θ) + T_{2} \cos θ = 100$

And $T_{1} \cos θ = T_{2} \cos (90 - θ)$

Solving, $T_{1} = 80 N$

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