A light wave is incident normally over a slit of width 24 x 10^-5 cm. The angular position of second dark fringe from the central maxima is 30^o. What is the wavelength of light

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$6000 \overset{0}{A}$

$5000 \overset{0}{A}$

$3000 \overset{0}{A}$

$1500 \overset{0}{A}$

answer is A.

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Detailed Solution

For second dark fringe $dsin θ = 2 λ$
$\begin{array}{l} \Rightarrow 24 \times 10^{- 5} \times 10^{- 2} \times \sin 30^{0} = 2 λ \\ \Rightarrow λ = 6 \times 10^{- 7} m = 6000 Å \end{array}$

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