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Q.

A line is drawn from the point P(1,1,1) and Perpendicular to a line with direction ratios (1,1,1) to intersect the plane x + 2y + 3z = 4 at Q. The locus of point Q is

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a

x2=y3=z5

b

x1=y−5−2=z+21

c

x=y=z

d

x−2=y−51=z+21

answer is A.

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Detailed Solution

Locus of Q is the line of intersection of the plane

x+2y+3z=4 and

1(x−1)+1(y−1)+(z−1)=0 then line is

x1=y−5−2=z+21

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