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A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength 5 x 10^-5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is :

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0 .20 cm

0.15 cm

0.10 cm

0.25 cm

answer is B.

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Detailed Solution

f = D = 60 cm

For first minima,

$y = \frac{λD}{a} = \frac{5 \times 10^{- 7} \times 60}{2 \times 10^{- 2} \times 10^{- 2}} - \frac{5 \times 10^{- 3} \times 60}{2} = 0 .15 cm$

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