A linear harmonic oscillator of force constant 2 × 10⁶ N/m and amplitude 0.01m has a total mechanical energy of 160 joules. Its

Elastic potential energy = $\frac{1}{2}{\mathrm{kx}}^2$ == (2 × 10⁶) (0.01)² = 100 J
The energy is converted into kinetic energy
$\therefore$maximum K.E. = 100 J
Given that total mechanical energy is 160 J , hence maximum potential energy is 160 J.