A linear harmonic oscillator of force constant $2\times {10}^6\mathrm{N}/\mathrm{m}$ and amplitude 0.01m has a total mechanical energy of 160J. Which of the following statement is correct.

${\mathrm{KE}}_{\max }=\frac{1}{2}{\mathrm{KA}}^2=\frac{1}{2}\times 2\times {10}^6\times {10}^{-4}=100 \mathrm{J}$

At the extreme position all the energy is potential energy = 160 J. i.e. At the equilibrium position, potential energy is not equal to Zero. It is minimum and is equal to 60 J.