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A liquid at $30^{0} C$ is poured very slowly into a Calorimeter that is at temperature of $110^{0} C .$ The boiling temperature of the liquid is $80^{0} C .$ It is found that the first 5gm of the liquid completely evaporates. After pouring another 100 gm of the liquid, the equilibrium temperature is found to be $50^{0} C .$ Then the ratio of the latent heat of the liquid to its specific heat will be …….. $^{0} C .$ [Neglect the heat exchange with surrounding]

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answer is 350.

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Detailed Solution

C be the specific heat and L be the latent heat of vapourisation. From principle of calorimetry,

Heat lost = heat gain

$M_{C} S_{C} Δ T = m C Δ T + m L o r M_{C} S_{C} (110 - 80) = 5 C (80 - 30) + 5 L ....... (i)$

Again, when 100 g liquid is poured and equilibrium temperature is $50^{0} C$

$m_{C} S_{C} (80 - 50) = 100 C (50 - 30) .......... (i i)$

$∴ \frac{L}{C} = \frac{1750}{5} = 350^{0} C$

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