A liquid enters a tube of variable cross section with a velocity 3 ms^-1 through the wider end and leaves from the narrower end whose radius is half of the wider one. The velocity with which it leaves the tube is

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12 ms^-1

10ms^-1

20 ms^-1

1.2 ms^-1

answer is B.

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Detailed Solution

$\begin{array}{l} V = 3 m / s; r_{1} = r, r_{2} = \frac{r}{2} \\ A_{1} v_{1} = A_{2} v_{2} \Rightarrow r_{1}^{2} v = r_{2}^{2} v_{2} \\ r^{2} (3) = {(\frac{r}{2})}^{2} v_{2} \Rightarrow v_{2} = 12 m / s \end{array}$

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